Pawbulouscatask
a fost răspuns

se considera numerele a= ([tex]\sqrt{27}[/tex] +2[tex]\sqrt{12}[/tex] - [tex]\frac{6}{\sqrt{3} }[/tex] * [tex]\frac{5}{\sqrt{3} }[/tex]) si b =[tex](0,(3))^{-1}[/tex].


aflati [tex](8b-a)^{101}[/tex]

Răspuns :

Ignatovvlad201ask
a)3V3+4V3-30/3=7V3-10
b)(0,(3))^-1=(3/9)^-1=(1/3)^-1=3
(8b-a)^101=(8*3-7V3-10)^101=(24-7V3-10)^101=
(14-7V3)^101.