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metoda mersului invers

1100-[(128×4-144:×)×2]=172


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Răspuns :

Jojoi54ask

Răspuns:

1100-[(128×4-144:×)×2]=172

[(128×4-144:×)×2]=1100-172

(512-144:x)X2=928

(512-144:x)=928:2

512-144:x=464

144:x=512-464

144:x=48

x=144:48

x=3

Oofyask

1100-(ax2)=172

1100-b=172

b=1100-172

b=928

ax2=928

a=928:2

a=464

128x4-144:x=464

512-c=464

c=512-464

c=48

144:x=48

x=144:48

x=3

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