Răspuns:
a ) x ∈ { 1, 9 }
b) x ∈ { 0, 6 }
Explicație pas cu pas:
a)
x ∈ N
[tex]\frac{17}{2x-1}[/tex] ∈ N => 2x-1 ∈ D₁₇
2x-1 ∈ { 1, 17 } | +1
2x ∈ { 2, 18 } | : 2
x ∈ { 1, 9 }
b)
x ∈ N
[tex]\frac{x+8}{x+1}[/tex] ∈ N => x+1 / x+8 ( x+1 divide x+8 )
dar x+1 / x+1
--------------------( - )
x+1/ 7 => x+1 ∈ D₇
x+1 ∈ { 1, 7 } | -1
x ∈ { 0, 6 }
