N2 + 3H2 --> 2NH3
pe reactie:
3 moli H2...................2 moli NH3
6 moli H2...................x
x= 6*2 / 3 = 12/3 = 4 moli NH3
1 mol...................6,022*10^23 molecule (numarul lui Avogadro)
4 moli..................x
x= 4 * 6,022*10^23 = 24,088 *10^23 molecule NH3
