Răspuns:
a)
[tex]=\frac{\sqrt{4*3} }{\sqrt{49} } -\frac{\sqrt{9*3} }{\sqrt{25} } +\frac{\sqrt{16*3} }{\sqrt{121} } =[/tex]
[tex]=\frac{2\sqrt{3} }{7} -\frac{3\sqrt{3} }{5} +\frac{4\sqrt{3} }{11} =[/tex]
[tex]=\frac{5*11*2\sqrt{3} -7*11*3\sqrt{3} +7*5*4\sqrt{3} }{7*5*11} =[/tex]
[tex]=\frac{110\sqrt{3} -231\sqrt{3} +140\sqrt{3} }{385} =[/tex]
[tex]=\frac{19\sqrt{3}}{385}[/tex]
b)
[tex]=\frac{\sqrt{16*2} }{\sqrt{9*3} } -\frac{\sqrt{4*2} }{\sqrt{9*3} } +\frac{\sqrt{25*2} }{\sqrt{16*3} } =[/tex]
[tex]=\frac{4\sqrt{2} }{3\sqrt{3} } -\frac{2\sqrt{2} }{3\sqrt{3} } +\frac{5\sqrt{2} }{4\sqrt{3} } =[/tex]
[tex]=\frac{4*4\sqrt{2} -4*2\sqrt{2} +3*5\sqrt{2} }{3*4\sqrt{3} } =[/tex]
[tex]=\frac{16\sqrt{2} -8\sqrt{2} +15\sqrt{2} }{12\sqrt{3} } =[/tex]
[tex]=\frac{23\sqrt{2}}{12\sqrt{3} }[/tex]
Explicație pas cu pas:
