Răspuns:
Explicație pas cu pas:
[tex]T_{k+1} = C_{n}^{k} *a^{n-k}*b^{k}[/tex]
[tex](x\sqrt{x} )^{10-k}*x^{-2k} =x^{8} => (x*x^{1/2})^{10-k}*x^{-2k} = x^{8} =>x^{\frac{30-3k}{2}*x^{-2k}=x^{8} => x^{\frac{30-3k-4k}{2}}=x^{8} => \frac{30-6k}{2}=8[/tex]
30-7k=16 => 7k=30-16 => 7k = 14 => k=2 => [tex]T_{3} il contine pe x^{8}[/tex]
