a fost răspuns

determinați valorile njr natural x pt care 5/8 < 7/x+1​

Răspuns :

[tex] \frac{5}{8} < \frac{7}{x + 1} [/tex]

[tex] \frac{5}{8} - \frac{7}{x + 1} < 0[/tex]

Aducem la numitor comun.

[tex] \frac{5(x + 1) - 7 \times 8}{8(x + 1)} < 0[/tex]

[tex] \frac{5x + 5 - 56}{8x + 8} < 0[/tex]

[tex] \frac{5x - 51}{8x + 8} < 0[/tex]

[tex]5x - 51 < 8x + 8[/tex]

[tex] - 3x < 59[/tex]

[tex]x < \frac{ - 59}{3} [/tex]

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