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(acuma e corect)0+[(1+2×3)÷c+5]÷6=(78-69)÷9(aflați pe c)​

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Dianageorgiana794ask

Răspuns:

0+[(1+2×3)÷c+5]÷6=(78-69)÷9

0+[(1+6):c+5]:6=9:9

(7:c+5):6=1-0

7:c+5=1·6

7:c=6-5

c=7:1

c=7

0 + [ ( 1 + 2 × 3 ) : c + 5 ] : 6 = ( 78 - 69 ) : 9

0 + [ ( 1 + 6 ) : c + 5 ] : 6 = 9 : 9

0 + ( 7 : c + 5 ) : 6 = 1

( 7 : c + 5 ) : 6 = 1 - 0

( 7 : c + 5 ) : 6 = 1

7 : c + 5 = 1 × 6

7 : c + 5 = 6

7 : c = 6 - 5

7 : c = 1

c = 7 : 1

c = 7

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