Răspuns :
1.
CH2=CH-CH2-CH3 + H2O --H+--> CH3-CH-CH2-CH3
OH
1-butena apa 2-butanol
CH3-CH-CH2-CH3 --toC/H+--> CH3-CH=CH-CH3
OH 2-butena
CH3-CH=CH-CH3 + 4[O] --energica--> 2CH3-COOH
acid etanoic (acetic)
2.
C4H8, M.C4H8 = 4x12+8x1 = 56 g/mol
56g C4H8 .... 4x12g C ...... 8x1g H
100% ............. a% ................ b%
= 85,71% C = 14,29% H