Răspuns:
[tex]\left \{ {{1,5x+0,(3)y=1,8} \atop {-3x+0,(6)y=1,6}} \right.[/tex]
[tex]\left \{ {{\frac{15x}{10}+\frac{3y}{9}=\frac{18}{10}} \atop {-3x+\frac{6y}{9}=\frac{16}{10}} } \right.[/tex]
[tex]\left \{ {{\frac{3x}{2}+\frac{y}{3}=\frac{9}{5}} /*30 \atop {-3x+\frac{2y}{3}=\frac{8}{5}} /*15 } \right.[/tex]
[tex]\left \{ {{45x+10y=54} \atop {-45x+10y=24}} \right.[/tex] |+
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/ +20y=74 /:2 10y=37 ⇒ y=37/10= 3 7/10
45x+10·37/10=54 45x+37=54 45x=17 x=17/45
Explicație pas cu pas:
