Răspuns:
Explicație pas cu pas:
[tex]m_{AB}=\frac{x_{B}-x_{A} }{y_{B} -y_{A} } =\frac{2+1}{-1-3} =-\frac{3}{4} \\ \\ \\m_{AB} m_{h} =-1\\ \\ m_{h} =-\frac{1}{m_{AB} } =\frac{4}{3} \\ \\ ecutia:\\ \\ y-y_{C} =m_{h} (x-x_{C} )\\ \\ y-6=\frac{4}{3} (x-3)\\ \\ y=\frac{4}{3} x-4+6\\ \\ y=\frac{4}{3} x+2[/tex]