Răspuns:
([tex]\frac{11}{3}[/tex]; [tex]\frac{-7}{3}[/tex])
Explicație pas cu pas:
[tex]\left \{ {{2x+y=5} \atop {9x+12y=5} \right.[/tex] ⇔[tex]\left \{ {{y=5-2x} \atop {9x+12(5-2x)=5}} \right.[/tex] ⇔[tex]\left \{ {{y=5-2x} \atop {9x+60-24x=5}} \right.[/tex] ⇔[tex]\left \{ {{y=5-2x} \atop {-15x=-55}} \right.[/tex]⇔[tex]\left \{ {{y=5-2x} \atop {x=\frac{11}{3} }} \right.[/tex] ⇔[tex]\left \{ {{y=5-2*(11/3)} \atop {x=11/3}} \right.[/tex] ⇔ [tex]\left \{ {{y=-7/3} \atop {x=11/3}} \right.[/tex]
