solutia 1:V=200ml=0,02 l
q=1,8 g/cm^3
C=50%
solutia 2:md=12 g H2SO4
100 g apa
Calculăm pentru prima solutie:
q=ms/Vs=>ms1=1,8*0,02=0,036 g H2SO4
C=md/ms*100
50=md/0,036*100
md=ms*100/C
md=0,036*100/50
md=3,6*5
md1=18 g
Calculăm pt a doua solutie masa solutiei
ms2=md2+mH2O=100+12=112 g
Acum calculăm pt solutia finala:
mdf=18+12=30g(md1+md2)
msf=0,036+112=112,036 g(ms1+ms2)
Cf=mdf/msf*100
Cf=112,036*30/100
Cf=3361/100
Cf=33,61%
Bafta!
