Răspuns:
a)4x-6≤10
4x≤10+6
4x≤16
x≤4
x∈(-∞;4]
b)2-7x=12
-7x=12-2
-7x=10
x=-10/7
e){x≥3
{x+4<0
{x≥3
{x<-4
x ∈Ф (x apartine multimii vide)
d)7x-3(2x-6)≥4-3(5x-1)
7x-6x+18≥4-15x+3
x+18≥7-15x
x+15x≥7-18
16x≥-11
x≥-11/16
x∈[-11/6;+∞)
bafta
