1. Na+ H2O = NaOH + 1/2 H2 ( reactie de substitutie )
CuSO4 + 2NaOH = Cu(OH)2 + Na2SO4 ( reactie de schimb )
2. Solutia de H2SO4 contine md = 10/100 * 61,25 = 6,125 g H2SO4
n H2SO4 = 0,0625 moli H2SO4
H2SO4 + 2NaOH = Na2SO4 + 2H2O
Asadar, n NaOH = 2 x 0,0625 = 0,125 moli NaOH => 5g NaOH
c NaOH = 8% , deci ms = 100/8 * 5 = 62,5 g solutie NaOH 8%
