265 g impur ............................ 100%
m g pur .................................... 80%
= 212 g Na2CO3 pur
a)
212 g n g a g
Na2CO3 --toC--> Na2O + CO2
106 62 44
=> a = 212x44/106 = 88 g CO2
=> n = 212x62/106 = 124 g Na2O
b)
124 g md g
Na2O + 2HCl --> 2NaCl + H2O
62 2x36,5
=> md = 124x2x36,5/62 = 146 g HCl
din c% = mdx100/ms
=> ms = mdx100/c%
cred ca c% = 36,5%.... si nu 35%
= 146x100/36,5 = 400 g sol. HCl