Răspuns:
Explicație pas cu pas:
6/12 si 14/21
6/12 = (6:6)/(12:6) = 1/2 -> fractie ireductibila
14/21 =(14:7)/(21:7) = 2/3 -> fractie ireductibila
-> cm.m.m.c al numitorilor 2 si 3 este 6
³⁾(1/2)=(3x1)/(3x2)=3/6
²⁾(2/3)=(2x2)/(2x3)=4/6
-> am adus fractiile ireductibile 1/2 si 2/3 la acelasi numitor comun 3/6 < 4/6
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5/20 = (5:5)/(20:5)=1/4 -> fractie ireductibila
22/55 = (22:11)/(55:11)=2/5 -> fractie ireductibila
->c.m.m.m.c al numitorilor 4 si 5 este 20
-> amplific fractia 1/4 cu 5, iar fractia 2/5 cu 4
⁵⁾(1/4) = (5x1)/(5x4)=5/20
⁴⁾(2/5) = (4x2)/(4x5) = 8/20
