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Calculati (3¹⁰⁰+3¹⁰⁰+3¹⁰⁰):3⁹⁸+5⁰.

54min18s+34min47s=

Suma a 10 numere pare nenule  distincte este 110 .Aflati numerele

Răspuns :

Miky93ask
1) (3¹⁰⁰  +3¹⁰⁰ +3¹⁰⁰ ) : 3⁹⁸ + 5⁰=

3¹⁰⁰(1+1+1) :3⁹⁸ +1=

= 3² * 3+1 =

= 27+1=28

2)54° 18' + 34⁰ 47' = 89⁰ 5'

3)(2k+2+2k+4+2k+6+2k+8+2k+10+2k+12+2k+14+2k+16+2k+18+2k+20)=110

20k+ 110=110

20k=110-110

20k=0

k=0

a=2k+2=2*0+2=2
b=0+4=4
c=6
d=8
e=10
f=12
g=14
h=16
i=18
j=20

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