Răspuns :
aducand la acelasi numitor aevem
[(-12+15-10)/30:7/15]³+1/8=
(-7/30.15/7)³+1/8=
(-1/2)³+1/8=-1/8+1/8=0
[(-12+15-10)/30:7/15]³+1/8=
(-7/30.15/7)³+1/8=
(-1/2)³+1/8=-1/8+1/8=0
[tex][ (-\frac{2}{5}^{(6}+\frac{1}{2}^{(15} -\frac{1}{3}^{(10} ): \frac{7}{15} ]^3 +\frac{1}{8} = ( \frac{-12+15-10}{30} * \frac{15}{7})^3 + \frac{1}{8} = \\ \\ =(-\frac{7}{2} * \frac{1}{7})^3 + \frac{1}{8}= (-\frac{1}{2})^{(3} + \frac{1}{8}= \\ \\ =- \frac{1}{8} + \frac{1}{8}\ = \boxed{0}[/tex]