doi frati au impreuna 1000 de surprize.daca primul ar da 100 de surprize,iar al doilea si-ar dubla numarul celor avute,amindoi ar avea acelasi nr de surprize.cite surprize are fiecare?

Răspuns :

x+y=1000

x-100= 2y
x=2y+100

2y+100+y=1000
3y=1000-100
3y=900
y=300

x=1000-300
x=700
x+y=1000
x-100 = 2y
x=2y+100
2y+100+y=1000
3y=1000-100
3y=900
y=900:3
y=300

x= 2x300 + 100
x=600+100
x=700