[tex] \frac{x+2}{x-1}-\frac{x+5}{x+1} =3[/tex]
aducem la acelasi numitor comun
[tex][tex](x+1)(x+2)-(x-1)(x+5)=3 x^{2}-3 \\ \\ x^{2} +2x+x+2- x^{2} -5x+x+5- 3x^{2} +3=0 \\ \\ -3 x^{2} -x+10=0 \\ \\ a=-3 \\ b=-1 \\ c=10 \\ \\ Δ=b ^{2}-4ac \\ ]Δ=(-1) ^{2} -4(-3*10) \\ \\ Δ=121 \\ \\ x_{1,2} = \frac{-b+-\sqrt{Δ} }{2a} [/tex][/tex][tex] x_{1,2}= \frac{-1+-11}{-6} \\ \\ x_{1} = \frac{-1-11}{-6} \\ \\ x_{1}=2 \\ \\ x_{2} = \frac{-1+11}{-6} \\ \\ x_{2}= \frac{10}{-6} \\ \\ x_{2} = \frac{5}{-3}
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