a fost răspuns

Calculati media geometrica a numerelor [tex]a= \sqrt{81}-3 \sqrt{3} + \sqrt{27} [/tex] si [tex]b=|2- \sqrt{3} |+ \frac{1}{2- \sqrt{3} } [/tex]

Răspuns :

Yukiiask
a=9-3√3+3√3=9
b=| √4 - √3 | +  2-√3/(2-√3)(2+√3) = -√4+√3 + 2-√3/4-3=-2+√3+2-√3=0

[tex] \sqrt{ab} [/tex] = [tex] \sqrt{9*0} [/tex] = √0 = 0

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