(2x+1)/3-(x-2)/5+(7x+5)/15 aducem la acelasi numitor
[5(2x+1)-3(x-2)+7x+5]/15
10x+5-3x+6+7x+5=0
14x+16=0
14x=-16
x=-16/14 simplificam
x=-8/7
2) x-pretul initial
20/100·x=2x/10 simplificam=x/5
x-x/5=320
(5x-x)/5=320
4x/5=320
4x=320·5
x=1600/4
x=400 lei