Răspuns:
[tex]\sqrt{27}(4\sqrt{32}-\sqrt{128})-\sqrt{32}(\sqrt{363}-\sqrt{147})=\\=3\sqrt{3}(4*4\sqrt{2}-8\sqrt{2})-4\sqrt{2}(11\sqrt{3}-7\sqrt{3})=\\=3\sqrt{3}*8\sqrt{2}-4\sqrt{2}*4\sqrt{3}=\\=24\sqrt{6}-16\sqrt{6}=8\sqrt{6}[/tex]
Explicație pas cu pas:
