Răspuns :
1) 4.35
2)x= 3.9
3)x*4=x+3/4=> 4x=4x/4+3/4 => 16x/4=(4x+3)/4 | *4
16 x= 4x+3 => 12x = 3=> x=1/4
Puncte? :D
2)x= 3.9
3)x*4=x+3/4=> 4x=4x/4+3/4 => 16x/4=(4x+3)/4 | *4
16 x= 4x+3 => 12x = 3=> x=1/4
Puncte? :D
1.x=3.15+1.2 Adica metoda drumului invers x=4.35
2.x ≤16.4-12.5
x ≤ 3.9
x={0 , 1 ,2 ,3 } apartine N
3.Ax4=a+ -
Ax4- =A +
Ax4=A
A=1
2.x ≤16.4-12.5
x ≤ 3.9
x={0 , 1 ,2 ,3 } apartine N
3.Ax4=a+ -
Ax4- =A +
Ax4=A
A=1