1.
C3H8 + 5 O2 ---------------------> 3CO2 + 4 H2O + Q
C4H10 + 13/2 O2--------------------->4CO2 + 5H2O + Q
propan:butan = 1:2 (molar)
aflam nr de moli de propan
notez cu M = masa molara si N nr de moli
Mpropan = 3x12+8 = 36+8 = 42 g/mol
N propan = 66/42 = 1,57 moli
din raport (1:2)
daca 1 mol propan....................2moli butan
1,57mol propan.................x=2 x 1,57 = 3,14moli butan
= amestecul contine 1,57 moli propan si 3,14 moli butan
1 mol propan degaja 3 moli CO2
1,57........................................y
y= 1,57x3 =.... .calculezi tu
1 mol butan degaja 4 moli CO2
3,14..........................................z
z= 3,14x4 =..... calculezi
cantitatea de CO2 formata = y+z (in moli)....
restul probl... se fac la fel... grija la calcule!