Răspuns:
X 1s2/2s2,2p6/3s2,3p6/4s2,3d6 Fe gr VIIIsec,per4
E 1s2/2s2,2p6/3s23p5 Cl gr VII princ, per3
2Fe+3Cl2=2FeCl3
b) FeCl3 M=162,5
162,5g FeCl3..........56gFe..............3x35,5g Cl
100g.........................X........................Y
X=100x56/162,5=34,46
Y=100x106,5/162,5=65,54
c)56g Fe........................162,5g FeCl2
3g...................................X
X=3x162,5/56=8,7 =cant teoretica (ct)
7,84 =cant practica(cp)
rand=(cp/ct) x100 =(7,84/8,7)x100=90.11
Explicație: