(x+3)²+2(x+1)²=11
x²+6x+9+2(x²+2x+1)=11
x²+6x+9+2x²+4x+2=11
3x²+10x+11=11
3x²+10x+11-11=0
3x²+10x+0=0
3x²+10x=0
rezolvăm prin delta
a=3
b=10
c=0
delta (∆)= b²-4ac= 10²-(4•3•0)=100-0=100
x1= -b-√∆/2a = -10-√100/2•3 = -10-10/6=-20/6=-10/3
x2 = -b+√∆/2a = -10+10/6=0/6=0
a) Soluția = {-10/3,0}
b) -10/3•0=0
