Răspuns:
Bună,
[tex]A = 3 \sqrt{48} + 6 \sqrt{12} + 3 \sqrt{147} \\ = 12 \sqrt{3} + 12 \sqrt{3} + 21 \sqrt{3} \\ = 45 \sqrt{3} [/tex]
[tex]B = 6 \sqrt{72} + 3 \sqrt{162} - 6 \sqrt{32} \\ = 36 \sqrt{2} + 27 \sqrt{2} - 24 \sqrt{2} \\ = 39 \sqrt{2} [/tex]
[tex] \frac{A}{B} = \frac{45 \sqrt{3} }{39 \sqrt{2} } \\ = \frac{15 \sqrt{3} }{13 \sqrt{2} } \\ \frac{15 \sqrt{3} \times \sqrt{2} }{13 \times 2} \\ = \frac{15 \sqrt{6} }{26} [/tex]
[tex]A \times B = 45 \sqrt{3} \times 39 \sqrt{2} \\ = 1755 \sqrt{6} [/tex]
Sper că te-am ajutat
