Răspuns:
Explicație pas cu pas:
4a) f'(x) = -16x +1
b) f'(x) = (x-3)'(x+1) - (x-3)(x+1)'/(x+1)^2 =
(x+1 -x +3)/(x+1)^2 = 4/(x+1)^2
5a) f'(x) = 4(x^3 +x)^3*(x^3+ x)' = 4(x^3 +x)^3*(3x^2 +1)
b) f'(x) = (3x+1)'/(2√(2x +1)) = 3/(2√(2x +1))
6c) i^2 = -1, -i^2 = 1
(2+i)(3-4i)/((3+4i)(3-4i))=
(6 -8i +3i -4i^2)/(9-16i^2)=
(10 -5i)/(9+16) = 5(2-i)/25 = (2 -i)/5
