Răspuns:
Explicație pas cu pas:
(un intreg1/3-5)²:7/2+[0,(1)]⁰ =
(4/3 - 5)^2 : 7/2 + 1 =
(4-15 / 3)^2 : 7/2 + 1 =
(-11/3)^2 : 7/2 + 1 =
121/9 x 2/7 + 1 =
242/63 + 1 =
3si53/63 + 1 =
4 si 53/63.
[tex]\it \Big(1\dfrac{1}{3}-5\Big)^2:\dfrac{7}{2}+\[[0,(1)]^0=\Big(-3\dfrac{2}{3}\Big)^2\cdot\dfrac{2}{7}+1=\Big(\dfrac{11}{3}\Big)^2\cdot\dfrac{2}{7}+1=\\ \\ \\ =\dfrac{121}{9}\cdot\dfrac{2}{7}+1=\dfrac{242}{63}+1=3\dfrac{53}{63}+1=4\dfrac{53}{63}[/tex]
