Răspuns:
a) 2√3 +2√3 -2√3= √3
[tex]b) \\ 5 \sqrt{2} + \frac{12}{ \sqrt{3} } - 10 \sqrt{2} = \\ 5 \sqrt{2} + 4 \sqrt{3} - 10 \sqrt{2} = \\ - 5 \sqrt{2} + 4 \sqrt{3} [/tex]
c)
[tex] \frac{5 \sqrt{2} }{2} + \frac{7 \sqrt{2} }{6} - \frac{2}{ \sqrt{2} } = \\ \frac{5 \sqrt{2} }{2} + \frac{7 \sqrt{2} }{6} - \sqrt{2} = \frac{8 \sqrt{2} }{3} [/tex]
