Danielduna22ask
a fost răspuns

demonstratti ca:
c) (4n+5, 5n+6)=1:
d) (2n+1, 3n+2)=1:​

Răspuns :

Laurentiupantilimon2ask

Răspuns:

c)

4n+5=1=>4n=-4=>n=-1

5n+6=1=>5n=-5=>n=-1

4×(-1)+5=-4+5=1

5×(-1)+6=-5+6=1

d)

2n+1=1=>2n=0=>n=0

3n+2=1=>3n=-1=>n=-1/3

2×0+1=0+1=1

3×(-1/3)+2=-1+2=1

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