[tex]\bf 2.\ \ \it p=\dfrac{nr.\ cazuri\ favorabile}{nr.\ cazuri\ posibile}=\dfrac{5}{5+11}=\dfrac{5}{16}\\ \\ \\ \bf 3.\ \ \it 10\%\ din\ 20=\dfrac{10}{100}\cdot20=\dfrac{200}{100}=2 \ell ei\ (reducerea)\\ \\ \\ 20-2=18 \ell ei\ (pre\c{\it t}ul\ nou)\\ \\ \\ \dfrac{\ 18^{(2}}{20}=\dfrac{9}{10}\ (raportul\ cerut)[/tex]
