Răspuns:
a. v1= (o,2-0,05)/(30-0)=0,005=-5x10⁻³mol/lxs
b. (0,05-c3)/15=1,66x10⁻⁻³----> c3=0,025mol/.l
c. 8,33x10⁻⁴=(0,025-0,0125)/t------> t= 15s
d. V= -1/1 ΔC,A/Δt= =1/2ΔC,B/Δt.----> V= 2X5X10⁻³= 10⁻²mol/lxs
Explicație:
