Media geometrica a doua numere este radical din produsul lor.
[tex] \sqrt{ab} = \sqrt{(5 \sqrt{12} + 3 \sqrt{27} - 9 \sqrt{3} )( \sqrt{48} + 2 \sqrt{3} - \sqrt{75} } [/tex]
Se scot factorii de sub radical. Iti scriu 2 exemple pe larg, restul se scot la fel:
[tex]\sqrt{12 = } \sqrt{4 \times 3} = \sqrt{ {2}^{2} \times 3} = 2 \sqrt{3} \\ \sqrt{27} = \sqrt{9 \times 3} = 3 \sqrt{3} [/tex]
Asadar,
[tex] \sqrt{ab} = \sqrt{(10 \sqrt{3} + 9 \sqrt{3} - 9 \sqrt{3} )(4 \sqrt{3} + 2 \sqrt{3} - 5 \sqrt{3} )} \\ = \sqrt{10 \sqrt{3} \times \sqrt{3} } = \sqrt{10 \times 3} = \sqrt{30} [/tex]
