Răspuns:
Conditiile de existenta ale radicalilor
x+1≥0
x≥ -1
9-x≥0
x≤9
2x-12≥0
x-6≥0
x≥6
x∈[-1,+∞)∩(-∞,9]∩[6,+∞)=[6,9]=DVA
Ridici ecuatia la patrat
x+1+9-x-2√(x+1)(9-x)=2x-12
10-2√(x+1)(9-x)=2x-12
-2√(9x+9-x²-x)=2x-22║:2
-√(-x²+8x+9)=x-11
Ridici relatia la patrat
-x²+8x+9=x²-22x+121
-2x²+30x-112=0:║:(-2)
x²-15x+56=0
x1=7∈DVA
x2=8∈DVA
Explicație pas cu pas:
