Răspuns:
[tex]\bf 2^{85} \cdot 7 = \big(2^{5} \big)^{17} \cdot 7 =32^{17} \cdot 7[/tex]
[tex]\bf 5^{34} \cdot 7 = \big(5^{2} \big)^{17} \cdot 6 =25^{17} \cdot 6[/tex]
[tex]\bf 32~>25~si ~7>6~\implies \red{\underline{2^{85} \cdot 7 ~ >~5^{34} \cdot 6}}[/tex]