Răspuns :
Răspuns:
2^100:[2^50×2^48+(2^10×2^15)^5:2^27+(5^76:5^75-3)^90×2^8+2^98]=
2¹⁰⁰:[2⁵⁰⁺⁴⁸+(2¹⁰⁺¹⁵)⁵:2²⁷+(5-3)⁹⁰·2⁸+2⁹⁸]=
2¹⁰⁰:(2⁹⁸+2²⁵⁰⁵:2²⁷+2⁹⁰·2⁸+2⁹⁸)=
2¹⁰⁰:(2⁹⁸+2¹²⁵⁻²⁷+2⁹⁸+2⁹⁸)=
2¹⁰⁰:(2⁹⁸+2⁹⁸+2⁹⁸+2⁹⁸)=
2¹⁰⁰:2⁹⁸·(1+1+1+1)=
2¹⁰⁰:(2⁹⁸·2²)=
2¹⁰⁰:2⁹⁸⁺²=
2¹⁰⁰:2¹⁰⁰=1