Răspuns:
a)
[tex]\sqrt{12}=\sqrt{4*3} =\sqrt{2^{2}*3}=2\sqrt{3} \\\sqrt{18} =\sqrt{49*2} =\sqrt{3^{2}*3}=3\sqrt{2}\\\sqrt{27} =\sqrt{9*3} =\sqrt{3^{2}*3}=3\sqrt{3}\\\sqrt{32} =4\sqrt{2} \\\sqrt{75} =5\sqrt{3}\\\sqrt{98} =7\sqrt{2}[/tex]
Explicație pas cu pas:
