Răspuns:
[tex] {2}^{2015} ( {2}^{2} + 2 + 1) \div {2}^{2008} ( {2}^{2} + 2 + 1) = {2}^{7} = 128[/tex]
[tex] {2017}^{2016} (2017 - 2016 - 1) = 0[/tex]
