Răspuns:
13 b) [123+2^7x2^2+2^67:2^27]:[123+2^14-2^5+(2^5)^8]=
=(123+2^9+2^40):(123+2^9+2^40)= Hai sa le aranjam un pic!
(123:123)+(2^9:2^9)+(2^40:2^40)=
=1+1+1=3 (abia ce am vazut ca am scris la raspuns oof)
acu fac si restu stai
e) De data asta hai sa le aducem pe toate la aceiasi baza da?
0^6=0
[2^8+(3^2)^2+5^6+(6^2)^2]:[(2^2)^4+3^4+(5^2)^3+6^4=
=(2^8+3^4+5^6+6^4):(2^8+3^4+5^6+6^4)=
=(2^8:2^8)+(3^4:3^4)+(5^6:5^6)+(6^4:6^4)=
=1+1+1+1=4
