Răspuns:
Explicație pas cu pas:
[tex]\bf e)~25^8:125^5=(5^2)^8:(5^3)^5=5^{2\cdot8}:5^{3\cdot5}=[/tex]
[tex]\bf 5^{16}:5^{15}=5^{16-15}= \purple{\underline{5^{1}}}[/tex]
[tex]\bf f)~16^9:8^{12}=(2^4)^9:(2^3)^{12}=2^{4\cdot9}:2^{3\cdot12}=[/tex]
[tex]\bf2^{36}:2^{36}=2^{36-36}=2^0=\red{\underline{~1~}}[/tex]
