a) termenii din fata radicalului se va trece cu ridicare la puterea a 2
2V(3/8)= V(2^2 × 3/8)= V(3/2)
b) 1/2 V(12/5)= V[(1/2)^2 ×12/5]= V[1/4 × 12/5]= V[12/20]
c) 2/3V(2/3)= V[(2/3)^2 × (2/3)]= V[2/3]^3 = V[8/27]
d) 2/5V15 = V[(2/5)^2 × 15]= V[4/25×15]= V[12/5]
e) 5/3V12/100= V[(5/3)^2 × 12/100]= V[25/9×12/100] = V[1/3]
f) -3V(1/10)= V[(-3)^2 × 1/10]= V[9/10]
g) 12/10V(10/9)= V[(6/5)^2 × 10/9] = V[36/25 × 10/9]= V[8/5]
h) -3V(1/3)= V[(-3)^2 × 1/3]= V[9×1/3]= V3
