Răspuns:
[tex]\bf 3^{22}-3\cdot (3^2+3^3)+6^0=[/tex]
[tex]\bf 3^{22}-3\cdot (9+27)+1=[/tex]
[tex]\bf 3^{22}-3\cdot 36+1= 3^{22}-3\cdot 36+1=[/tex]
[tex]\bf 3^{22}-108+1=\red{\underline{~3^{22}-107~}}[/tex]