Răspuns :
Răspuns:
a) 2²⁰¹⁵(2²-2-1):2⁵:(2⁴)⁵⁰²+1·1=
2²⁰¹⁵·1:2⁵:2²⁰⁰⁸+1=
2²⁰¹⁵⁻⁵⁻²⁰⁰⁸+1=2²+1=3
b) [1+(3³)²⁷:(3²)⁴⁰]⁵⁰:(2⁵)²⁰=
(1+3⁸¹⁻⁸⁰)⁵⁰:2¹⁰⁰=
(1+3¹)⁵⁰:2¹⁰⁰=4⁵⁰:2¹⁰⁰=(2²)⁵⁰:2¹⁰⁰=2¹⁰⁰:2¹⁰⁰=1
c) 2⁸:(2²)³+3⁴:(64-36-1)=2⁸⁻⁶+3⁴:27=2²+3⁴:3³=4+3=7
Răspuns:
a) 2²⁰¹⁵(2²-2-1):2⁵:(2⁴)⁵⁰²+1·1=
2²⁰¹⁵·1:2⁵:2²⁰⁰⁸+1=
2²⁰¹⁵⁻⁵⁻²⁰⁰⁸+1=2²+1=3
b) [1+(3³)²⁷:(3²)⁴⁰]⁵⁰:(2⁵)²⁰=
(1+3⁸¹⁻⁸⁰)⁵⁰:2¹⁰⁰=
(1+3¹)⁵⁰:2¹⁰⁰=4⁵⁰:2¹⁰⁰=(2²)⁵⁰:2¹⁰⁰=2¹⁰⁰:2¹⁰⁰=1
c) 2⁸:(2²)³+3⁴:(64-36-1)=2⁸⁻⁶+3⁴:27=2²+3⁴:3³=4+3=7