Netamyhay18ask
a fost răspuns

Scoateți factorii de sub radicali:
a)
[tex] \sqrt{96} [/tex]
[tex] \sqrt{48} [/tex]
[tex] \sqrt{72} [/tex]
[tex] \sqrt{56} [/tex]
[tex] \sqrt{84} [/tex]
[tex] \sqrt{108} [/tex]
[tex] \sqrt{162} [/tex]
[tex] \sqrt{192} [/tex]
[tex] \sqrt{150} [/tex]
[tex] \sqrt{147} [/tex]
b)
[tex] \sqrt{ {2}^{2} } \times {3}^{2} + 3 \sqrt{576} [/tex]
[tex] \sqrt{ {2}^{3} } + 4 \sqrt{324} [/tex]

[tex] \sqrt{ {2}^{4} } + 2 \sqrt{289} [/tex]

[tex] \sqrt{ {6}^{2} } + 3 \sqrt{256} [/tex]
[tex] \sqrt{33 + 6 \sqrt{361} } [/tex]

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Răspuns :

Bozabeatriceask

Răspuns:

Explicație pas cu pas:

a)

[tex]\sqrt{96} = 4\sqrt{6} \\\sqrt{48} = 4\sqrt{3} \\\sqrt{72} = 6\sqrt{2} \\\sqrt{56} =2\sqrt{14} \\\sqrt{84} =2\sqrt{21} \\[/tex][tex]\sqrt{108} =6\sqrt{3} \\\sqrt{162} =9\sqrt{2} \\\sqrt{192} =8\sqrt{3} \\\sqrt{150} =5\sqrt{6}\\\sqrt{147} = 7\sqrt{3}[/tex]

b)

[tex]2*9+3*24= 18+72= 90\\\\2\sqrt{2} +4*18= 2\sqrt{2} +72\\\\4+2*17= 4+34= 38\\\\6+3*16= 6+48=54\\\\\sqrt{33+6*19} =\sqrt{33+114} =\sqrt{147} =7\sqrt{3}[/tex]

Sper ca te-am ajutat!