Răspuns:
[tex]\bf c)~2\sqrt{6} \cdot 4\sqrt{3}\cdot(-1)=8\sqrt{18} \cdot(-1)=-8\sqrt{3^{2}\cdot2}=\blue{\underline{-24\sqrt{2} ~}}[/tex]
[tex]\bf d) ~\sqrt{9} \cdot 5\sqrt{4}\cdot\sqrt{1} =\sqrt{3^{2}} \cdot5\sqrt {2^{2}}\cdot 1=3\cdot5\cdot 2\cdot 1 =\purple{\underline{~ 30 ~}}[/tex]
