Răspuns:
Explicație pas cu pas:
[tex]\bf a)~ 2^9 + 2^9 = 2 \cdot 2^9 = 2^{10} = \Big(2^5\Big)^2[/tex]
[tex]\bf b)~ 2^{11} + 2^{11} = 2 \cdot 2^{11} = 2^{12} = \Big(2^6\Big)^2[/tex]
[tex]\bf c)~ 3^7 + 3^7 + 3^7 = 3 \cdot 3^7 = 3^8 = \Big(3^4\Big)^2[/tex]
[tex]\bf d) ~3^6 + 3^7 = 3^6 \cdot (1 + 3) = 4 \cdot 3^6 = 2^2 \cdot 3^6 = \Big(2\cdot3^3\Big)^2[/tex]
[tex]\bf e)~ 5^9 - 5^8 = 5^8 \cdot (5 - 1) = 4 \cdot 5^8 = 2^2 \cdot 5^8 =\Big(2\cdot5^4\Big)^2[/tex]
[tex]\bf f)~ 8^5 \cdot 2^7 = (2^3)^5 \cdot 2^7 = 2^{15} \cdot 2^7 = 2^{22} = \Big(2^{11}\Big)^{2}[/tex]
[tex]\bf g) ~5^7 \cdot 25^3:5 = 5^7 \cdot (5^2)^3:5 = 5^7 \cdot 5^6 : 5 = 5^12 = \Big(5^6\Big)^2[/tex]
[tex]\bf h)~ 3^{11} + 9^5 = 3^{11} + (3^2)^5 = 3^{11} + 3^{10} =[/tex]
[tex]\bf 3^{10} \cdot (3 + 1) = 4 \cdot 3^{10} = 2^2 \cdot 3^{10} = \Big(2\cdot3^5\Big)^{2}[/tex]
[tex]\bf i)~ (27^3)^5:3^{19} = 27^{15}:3^{19} = (3^3)^{15}:3^{19} = 3^{45}:3^{19} = 3^{26} = \Big(3^{13}\Big)^2[/tex]
