Răspuns:
b).4
c).3
Explicație pas cu pas:
b).(2^8*2^12)^7:(2^6)^23=
2^8*7*2^12*7:2^6*23=
2^56*2^84:2^138=
2^140:2^138=2^2=4
c). (3^n+1)^2:3^2n+1=
3^2*n+1*2:3^2n+1=
3^2n+2:3^2n+1=3^1=3
^-ridicare la putere
*-inmultire
sper ca te-am ajutat
